If it's not what You are looking for type in the equation solver your own equation and let us solve it.
2n^2+3n-54=0
a = 2; b = 3; c = -54;
Δ = b2-4ac
Δ = 32-4·2·(-54)
Δ = 441
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{441}=21$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-21}{2*2}=\frac{-24}{4} =-6 $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+21}{2*2}=\frac{18}{4} =4+1/2 $
| 6(x-2)+4=42-2x | | 0=-4.9t^2+30t+6 | | 6x=32+14-4x | | 5(2x-7)-3x+2=4-(4x-7) | | 24(3–k/2)=8k+72(k+1) | | 122=-38+4x | | (4x+10)+(2x+20)=90 | | 32=-38-10x | | 30(x-5)=28x-51 | | -29=-8+x/4 | | 8x17/8=- | | 12x-2=6x+22 | | R=2w+3 | | 12x–2=6x+22 | | v^2-16v-23=0 | | -3x+10=3x+8 | | 6(1-3x)-2x=26 | | -2y+7=3y-3 | | -179=-67-14x | | 6.5g+2=1.5g+22 | | 3(7+-1.5y)-4y=4 | | 12x-8=-4x+8 | | 2x+3=3x-22 | | 6n+2(3n+4)=32 | | 4=6+x/4 | | 90=9(s+6) | | 4x-37=2x-3 | | (3x+6)+(8x-4)=90 | | 3m-10=-100 | | d-7/2=1 | | -5(2x+8)=-100 | | -3y-2=19 |